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Given a non-empty string and an int n, return a new string where the char at index n has been removed. The value of n will be a valid index of a char in the original string (i.e. n will be in the range 0..str.length()-1 inclusive). missingChar("kitten", 1) → "ktten" missingChar("kitten", 0) → "itten" missingChar("kitten", 4) → "kittn" ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 130.0
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