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Given three ints, a b c, return True if one of b or c is "close" (differing from a by at most 1), while the other is "far", differing from both other values by 2 or more. Note: abs(num) computes the absolute value of a number. close_far(1, 2, 10) → True close_far(1, 2, 3) → False close_far(4, 1, 3) → True ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 215.0
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