Java > String-1 > without2
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Given a string, if a length 2 substring appears at both its beginning and end, return a string without the substring at the beginning, so "HelloHe" yields "lloHe". The substring may overlap with itself, so "Hi" yields "". Otherwise, return the original string unchanged. without2("HelloHe") → "lloHe" without2("HelloHi") → "HelloHi" without2("Hi") → "" ...Save, Compile, Run public String without2(String str) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  String-1

Forget It! -- delete my code for this problem 187.0

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