Java > String-1 > hasBad
prev  |  next  |  chance

Given a string, return true if "bad" appears starting at index 0 or 1 in the string, such as with "badxxx" or "xbadxx" but not "xxbadxx". The string may be any length, including 0. Note: use .equals() to compare 2 strings. hasBad("badxx") → true hasBad("xbadxx") → true hasBad("xxbadxx") → false ...Save, Compile, Run public boolean hasBad(String str) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  String-1

Forget It! -- delete my code for this problem 160.0

Copyright Nick Parlante 2006-10 - privacy