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| Given a string, compute recursively a new string where all the lowercase 'x' chars have been moved to the end of the string.
endX("xxre") → "rexx" endX("xxhixx") → "hixxxx" endX("xhixhix") → "hihixxx" ...Save, Compile, Run See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops
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Forget It! -- delete my code for this problem 360.0
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