Java > Recursion-1 > countPairs
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We'll say that a "pair" in a string is two instances of a char separated by a char. So "AxA" the A's make a pair. Pair's can overlap, so "AxAxA" contains 3 pairs -- 2 for A and 1 for x. Recursively compute the number of pairs in the given string. countPairs("axa") → 1 countPairs("axax") → 2 countPairs("axbx") → 1 ...Save, Compile, Run public int countPairs(String str) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  Recursion-1

Forget It! -- delete my code for this problem 363.0

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