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This problem will only make sense after reading the HW3 writeup. Return the value of the pixel on the last row in the last column of the given pixel_grid. The pixel_grid will always contain at least one value. get_last_pixel([[5, 2, 3], [1, 5, 4]]) → 4 get_last_pixel([[1, 3], [3, 4], [15, 16], [9, 2]]) → 2 get_last_pixel([[100, 50]]) → 50 ...Save, Compile, Run (ctrl-enter) |
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