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Determine if a word has an odd or even amount of characters. oddOrEvenString("cat") → "cat has an odd amount of chars." oddOrEvenString("book") → "book has an even amount of chars." oddOrEvenString("1") → "1 has an odd amount of chars." Go...Save, Compile, Run (ctrl-enter)Show Hint public String oddOrEvenString(String word){ } Go Editor font size %:75100125150 Shorter output

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