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Given three strings, return a string that is composed of the first letter of the first string, the middle letter of the second string and the last letter of the third string. Each string is at least one character long and the middle string will contain an odd number of characters. formatWord("boat", "track", "refrain") → "ban" formatWord("12345", "9142568", "3") → "123" formatWord("c", "a", "r") → "car" ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 200 Post-solution available
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