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Write a method that returns true if there are an even number of 'target' numbers in the 'nums' array, and returns false otherwise. Note that having NO matches means there are ZERO matches, and zero is an even number, so you would return true in that case. Look at the test data for examples. ppp1evenNumOf([4, 5, 7, 2, 2, 4, 6, 1], 2) → true ppp1evenNumOf([6, 2, 3, 3, 3, 5, 0], 3) → false ppp1evenNumOf([6, 2, 3, 3, 3, 5, 0], 5) → false ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 290
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