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Write a python function called evenAndNotMultipleOf3 which has an input parameter, num, and returns true if num is even and not a multiple of 3 and false otherwise. evenAndNotMultipleOf3(4) → True evenAndNotMultipleOf3(7) → False evenAndNotMultipleOf3(12) → False ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 100
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