Given an input char, return the result of a one-character Caesar cipher where any letter is shifted up one letter. Precondition: the input char will have only a capital letter in it.

HINT #1

You can convert a char to a numeric data type like int by using casting syntax. Then it can be played with like any other int. You can cast an int to a char, as well. Here's an example:

char a = 'A';
int numA = (int)a;
numA = numA + 3;
char newChar = (char)numA; // newChar == 'D'

HINT #2

The ASCII (also UTF-8, used by Java) number representing 'A' is 65. There are 26 letters in the English alphabet, which could either be represented by the numbers 1 to 26 or (sometimes more useful mathematically) 0 to 25. What output should you get when the input is 'Z'?

The most elegant solution will use the remainder operator %, instead of a conditional or a ternary operator.