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gaurav1780@gmail.com 07_recursion > diff_dates1
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Define a recursive function that when passed two dates in the same year (assume non-leap year), returns the difference (in days) between the two. For example, there is a two-day difference between 13/04/2011 and 15/04/2011. You may not use any loops. You may create helper functions if needed.


diff_dates1(25, 7, 17, 8) → 23
diff_dates1(31, 3, 1, 4) → 1
diff_dates1(30, 4, 1, 5) → 1

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def diff_dates1(day1, month1, day2, month2):

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