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Write a method that accepts a number 'num' and a divisor 'div'. Return a string that tells the answer you get when 'num' is divided by 'div', using the old-school form of division where remainders are reported out. For example, if 'num' is 53 and 'div' is 5, you would return "10 remainder 3" because 5 goes into 53 ten times with a remainder of 3. Look at the test data for more examples. As a precondition you may assume that both 'num' and 'div' will be positive integers. test2021_02_11_APP1SLHL_longDivision(17, 3) → "5 remainder 2" test2021_02_11_APP1SLHL_longDivision(80, 10) → "8 remainder 0" test2021_02_11_APP1SLHL_longDivision(412, 6) → "68 remainder 4" ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 230
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