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Let's define the "semiproduct" of two positive integers to be the product of the sums of each of their digits. So the "semiproduct" of 21 and 71 is 24 because 2+1=3 and 7+1=8, then 3*8=24. Decompose out a separate digitSum(int n) method that finds the sum of the digits of a positive integer. semiProduct(18, 3) → 27 semiProduct(46, 73) → 100 semiProduct(12, 35) → 24 ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 325 Post-solution available
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