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APCS String 2, Problem 11. Given a string, return the longest substring that appears at both the beginning and end of the string without overlapping. For example, sameEnds("abXab") is "ab". S211_sameEnds("abXYab") → "ab" S211_sameEnds("xx") → "x" S211_sameEnds("xxx") → "x" Go...Save, Compile, Run (ctrl-enter) public String S211_sameEnds(String str) { } Go Editor font size %:75100125150 Shorter output

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