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Given a function f from {1, 2, . . . , n} to itself, determine whether f is onto. isOnto([1, 2, 3, 4], [4, 3, 1, 2], 4) → true isOnto([1, 1, 1, 1], [4, 3, 2, 1], 4) → true isOnto([1, 2, 3], [1, 2, 3], 3) → true ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 200
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