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simona1@sfusd.edu recursion3 > countOnes
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Given a non-negative int n, return the number of its digits that are equal to 1 recursively (no loops). Note that mod (%) by 10 yields the rightmost digit (126 % 10 is 6), while divide (/) by 10 removes the rightmost digit (126 / 10 is 12).


countOnes(121) → 2
countOnes(49) → 0
countOnes(12181) → 3

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public int countOnes(int n) { }

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