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hasOk
Given a string, return true if "ok" appears starting at index 1 or index 2 in the string, such as with "xok" or "xxok" but not "okx" or "xxxok". The string may be any length, including 0. Note: use .equals() to compare 2 strings. hasOk("okx") → false hasOk("xok") → true hasOk("ok") → false ...Save, Compile, Run (ctrl-enter) |
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