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apcsaArraysConcatThreeFirstCharacters
Requires String methods: skip if you do not know about substring yet Given an array of three Strings, return a String made up of the first character of each of the Strings, in the same order as the array. Precondition: the input array has exactly three elements, and each String in the input array will have length() >= 1.HINTYou could use a loop, or not. Your choice, since you know the number of array elements beforehand. Suggestion: use substring(n, n+1) to get a character out of each String. STRINGS VS ARRAYS Remember that Strings have length as a method, meaning a[0].length() instead of a[0].length. This gets confusing, and people often get it wrong the other way like a.length() instead of a.length - just come back up and look at this if you get confused. Also you can use a[0].substring()... apcsaArraysConcatThreeFirstCharacters(["a", "b", "c"]) → "abc" apcsaArraysConcatThreeFirstCharacters(["gl", "o", "b"]) → "gob" apcsaArraysConcatThreeFirstCharacters(["give ", "me ", "liberty"]) → "gml" ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 130
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