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public int getLargest2(int[] nums)
public int getLargest2(int[] nums) {
int largest = nums[0];
if (nums[1] > largest) {
largest = nums[1];
}
return largest;
}
Note: Another way to check for the larger of two values is to use Math.max():
public int getLargest2(int[] nums) {
int largest = Math.max( nums[0], nums[1] );
return largest;
}
getLargest2([5, 10]) → 10 getLargest2([10, 5]) → 10 getLargest2([3, 6]) → 6 ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 1
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