CodingBat has3nextTo3

has3nextTo3

Use recursion to search an array for a 3 next to a 3. Returns true if nums has a 3 next to a 3 somewhere and false otherwise. nums will have at least one element

has3nextTo3([1, 2, 3, 3], 0) → true
has3nextTo3([1, 2, 2, 3], 0) → false
has3nextTo3([3], 0) → false

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