dsawyer@methacton.org python_strings > space
prev  |  next  |  chance

Complete the function so that it returns True if the parameter contains at least one space. Do NOT use a loop. space('one space') → True space('nospaces') → False space(' oops') → True Go...Save, Compile, Run (ctrl-enter)Show Hint def space( x ): Go Editor font size %:75100125150 Shorter output

Forget It! -- delete my code for this problem

Progress graphs:
 Your progress graph for this problem
 Random user progress graph for this problem
 Random Epic Progress Graph

Python Help

• Python Example Code
• Python Strings
• Python Lists
• Python If Boolean
• Code Badges

Difficulty: 100 Post-solution available

Copyright Nick Parlante 2017 - privacy