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Given a String, return the same String but with a count of how many times each character in the original String appears immediately after each character. charCount("ABC") → "A1B1C1" charCount("ABBCCC") → "A1B2B2C3C3C3" charCount("ABCBCC") → "A1B2C3B2C3C3" ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 300
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