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Write a RECURSIVE method that returns the "digit double" of a non-negative integer. The "digit double" of a number is based on the original number having each digit doubled, provided that doubling the digit does not require carrying any part of the value to the next place-value. For example, the digit '3' can be doubled to make a '6', but the digit '7' will NOT get doubled, because the result would be 14 which would require carrying a '1' to the next higher place-value. For example, the number 120749 becomes 240789. Look at the test data for additional examples. Your solution MUST be recursive and you may NOT use any strings, chars, or loops. I suggest making a helper method just so your code is not so long when you make the recursive call to the method. may_14_2019_APSLHL_digitDouble(31) → 62 may_14_2019_APSLHL_digitDouble(342) → 684 may_14_2019_APSLHL_digitDouble(7) → 7 ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 440
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