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Given 2 strings, a and b, return the number of the positions where they contain the same length 2 substring. So "xxcaazz" and "xxbaaz" yields 3, since the "xx", "aa", and "az" substrings appear in the same place in both strings. stringMatch("xxcaazz", "xxbaaz") → 3 stringMatch("abc", "abc") → 2 stringMatch("abc", "axc") → 0 ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 227.0
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