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Given a non-empty string and an int N, return the string made starting with char 0, and then every Nth char of the string. So if N is 3, use char 0, 3, 6, ... and so on. N is 1 or more. everyNth("Miracle", 2) → "Mrce" everyNth("abcdefg", 2) → "aceg" everyNth("abcdefg", 3) → "adg" ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 190.0
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