String-2 > zipZap
prev  |  next  |  chance

Look for patterns like "zip" and "zap" in the string -- length-3, starting with 'z' and ending with 'p'. Return a string where for all such words, the middle letter is gone, so "zipXzap" yields "zpXzp". zipZap("zipXzap") → "zpXzp" zipZap("zopzop") → "zpzp" zipZap("zzzopzop") → "zzzpzp" Go...Save, Compile, Run (ctrl-enter) public String zipZap(String str) { } Go Editor font size %:75100125150 Shorter output

Forget It! -- delete my code for this problem

Progress graphs:
 Your progress graph for this problem
 Random user progress graph for this problem
 Random Epic Progress Graph

Java Help

• Java Example Solution Code
• Java String Introduction (video)
• Java Substring v2 (video)
• Java String Equals and Loops
• Java String indexOf and Parsing
• Java If and Boolean Logic
•   If Boolean Logic Example Solution Code 1 (video)
•   If Boolean Logic Example Solution Code 2 (video)
• Java For and While Loops
• Java Arrays and Loops
• Java Map Introduction
• Java Map WordCount
• Java Functional Mapping
• Java Functional Filtering

Misc Code Practice

• Code Badges
• Introduction to Mod (video)
• MakeBricks problem and solution (video x 2)
• FizzBuzz the famous code interview question (video)

Difficulty: 251.0

Copyright Nick Parlante 2017 - privacy