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| Given two ints, each in the range 10..99, return true if there is a digit that appears in both numbers, such as the 2 in 12 and 23. (Note: division, e.g. n/10, gives the left digit while the % "mod" n%10 gives the right digit.) shareDigit(12, 23) → true shareDigit(12, 43) → false shareDigit(12, 44) → false ...Save, Compile, Run (ctrl-enter) | 
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Difficulty: 166.0 Post-solution available
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