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Given an array of strings, return a Map<String, Integer> containing a key for every different string in the array, always with the value 0. For example the string "hello" makes the pair "hello":0. We'll do more complicated counting later, but for this problem the value is simply 0. word0(["a", "b", "a", "b"]) → {"a": 0, "b": 0} word0(["a", "b", "a", "c", "b"]) → {"a": 0, "b": 0, "c": 0} word0(["c", "b", "a"]) → {"a": 0, "b": 0, "c": 0} ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 303 Post-solution available
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