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Given a string, return true if the number of appearances of "is" anywhere in the string is equal to the number of appearances of "not" anywhere in the string (case sensitive). equalIsNot("This is not") → false equalIsNot("This is notnot") → true equalIsNot("noisxxnotyynotxisi") → true ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 309.0
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