id/email
password
forgot password | create account
about | help | code help+videos | done | prefs
CodingBat code practice

 

String-3 > mirrorEnds
prev  |  next  |  chance

Given a string, look for a mirror image (backwards) string at both the beginning and end of the given string. In other words, zero or more characters at the very begining of the given string, and at the very end of the string in reverse order (possibly overlapping). For example, the string "abXYZba" has the mirror end "ab".


mirrorEnds("abXYZba") → "ab"
mirrorEnds("abca") → "a"
mirrorEnds("aba") → "aba"

...Save, Compile, Run (ctrl-enter)

public String mirrorEnds(String string) { }

Editor font size %:
Shorter output


Forget It! -- delete my code for this problem

Progress graphs:
 Your progress graph for this problem
 Random user progress graph for this problem
 Random Epic Progress Graph

Java Help

Misc Code Practice

Difficulty: 324.0

Copyright Nick Parlante 2017 - privacy