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Given a string, return true if "bad" appears starting at index 0 or 1 in the string, such as with "badxxx" or "xbadxx" but not "xxbadxx". The string may be any length, including 0. Note: use .equals() to compare 2 strings. hasBad("badxx") → true hasBad("xbadxx") → true hasBad("xxbadxx") → false ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 160.0 Post-solution available
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