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Given a list of strings, return a list of the strings, omitting any string that contains a "z". (Note: the str.contains(x) method returns a boolean) noZ(["aaa", "bbb", "aza"]) → ["aaa", "bbb"] noZ(["hziz", "hzello", "hi"]) → ["hi"] noZ(["hello", "howz", "are", "youz"]) → ["hello", "are"] ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 209
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