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konstans@stuy.edu set1 > sumOfPositiveSquares
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Calculate the sum of the squares of the two argument provided. When a value is negative, it should be considered a 0 for the sake of this sum.


sumOfPositiveSquares(0.0, 0.0) → 0.0
sumOfPositiveSquares(1.0, 0.0) → 1.0
sumOfPositiveSquares(1.0, 2.0) → 5.0

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public double sumOfPositiveSquares(double a, double b){ }

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