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konstans@stuy.edu set1 > sumOfEvenRange
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Calculate the sum of all of the integers between the two argument provided. This includes the two values provided, however odd numbers are excluded. If the same number is given twice, return that number or 0 if it is odd. Assume start <= end. Hint: The body of a loop can contain a conditional!


sumOfEvenRange(1, 2) → 2
sumOfEvenRange(2, 5) → 6
sumOfEvenRange(3, 3) → 0

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public int sumOfEvenRange(int start, int end){ }

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