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Given an element and a sequence (either a string or a list), return a new sequence from which all occurrences of the element have been removed. Implement a recursive solution. removeAll('a', 'aaahaaia!a') → 'hi!' removeAll('a', ['a', 'a', 'a', 'h', 'a', 'a', 'i', 'a', '!', 'a']) → ['h', 'i', '!'] removeAll('b', 'bcbcbc') → 'ccc' ...Save, Compile, Run (ctrl-enter) |
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Difficulty: 200 Post-solution available
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