Java > Array-2 > tenRun
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For each multiple of 10 in the given array, change all the values following it to be that multiple of 10, until encountering another multiple of 10. So {2, 10, 3, 4, 20, 5} yields {2, 10, 10, 10, 20, 20}. tenRun({2, 10, 3, 4, 20, 5}) → {2, 10, 10, 10, 20, 20} tenRun({10, 1, 20, 2}) → {10, 10, 20, 20} tenRun({10, 1, 9, 20}) → {10, 10, 10, 20} ...Save, Compile, Run public int[] tenRun(int[] nums) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  Array-2

Forget It! -- delete my code for this problem 269.0

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