Java > String-3 > countYZ
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Given a string, count the number of words ending in 'y' or 'z' -- so the 'y' in "heavy" and the 'z' in "fez" count, but not the 'y' in "yellow" (not case sensitive). We'll say that a y or z is at the end of a word if there is not an alphabetic letter immediately following it. (Note: Character.isLetter(char) tests if a char is an alphabetic letter.) countYZ("fez day") → 2 countYZ("day fez") → 2 countYZ("day fyyyz") → 2 ...Save, Compile, Run public int countYZ(String str) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  String-3

Forget It! -- delete my code for this problem 303.0

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