Java > Warmup-1 > everyNth
prev  |  next  |  chance

Given a non-empty string and an int N, return the string made starting with char 0, and then every Nth char of the string. So if N is 3, use char 0, 3, 6, ... and so on. N is 1 or more. everyNth("Miracle", 2) → "Mrce" everyNth("abcdefg", 2) → "aceg" everyNth("abcdefg", 3) → "adg" ...Save, Compile, Run          Show Solution public String everyNth(String str, int n) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  Warmup-1

Forget It! -- delete my code for this problem 190.0

Copyright Nick Parlante 2006-10 - privacy