id/email | |

password | |

forgot password | create account | |

Or use |

about | help | code help+videos | done | prefs |

Logic-2 > roundSum

prev | next | chance

Forget It! -- delete my code for this problem### Java Help

### Misc Code Practice

prev | next | chance

For this problem, we'll round an int value up to the next multiple of 10 if its rightmost digit is 5 or more, so 15 rounds up to 20. Alternately, round down to the previous multiple of 10 if its rightmost digit is less than 5, so 12 rounds down to 10. Given 3 ints, a b c, return the sum of their rounded values. To avoid code repetition, write a separate helper "public int round10(int num) {" and call it 3 times. Write the helper entirely below and at the same indent level as roundSum(). roundSum(16, 17, 18) → 60 roundSum(12, 13, 14) → 30 roundSum(6, 4, 4) → 10 ...Save, Compile, Run |

Forget It! -- delete my code for this problem

Progress graphs:

Your progress graph for this problem

Random user progress graph for this problem

Random Epic Progress Graph

- Java Example Solution Code
- Java String Introduction (video)
- Java Substring v2 (video)
- Java String Equals and Loops
- Java String indexOf and Parsing
- Java If and Boolean Logic
- If Boolean Logic Example Solution Code 1 (video)
- If Boolean Logic Example Solution Code 2 (video)
- Java For and While Loops
- Java Arrays and Loops
- Java Map Introduction
- Java Map WordCount
- Java Functional Mapping
- Java Functional Filtering

- Code Badges
- Introduction to Mod (video)
- MakeBricks problem and solution (video x 2)
- FizzBuzz the famous code interview question (video)

Difficulty: 214 Post-solution available

Copyright Nick Parlante 2016 - privacy