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| Given a string, compute recursively (no loops) the number of "11" substrings in the string. The "11" substrings should not overlap.
count11("11abc11") → 2 count11("abc11x11x11") → 3 count11("111") → 1 ...Save, Compile, Run See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops
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Forget It! -- delete my code for this problem 369.0
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