Java > Warmup-1 > backAround
prev  |  next  |  chance

Given a string, take the last char and return a new string with the last char added at the front and back, so "cat" yields "tcatt". The original string will be length 1 or more. backAround("cat") → "tcatt" backAround("Hello") → "oHelloo" backAround("a") → "aaa" ...Save, Compile, Run          Show Solution public String backAround(String str) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  Warmup-1

Forget It! -- delete my code for this problem

New just for fun
 Random User Progress Graphs
 Random Epic Graphs 139.0

Copyright Nick Parlante 2006-11 - privacy