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Python > Logic-2 > close_far
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Given three ints, a b c, return True if one of b or c is "close" (differing from a by at most 1), while the other is "far", differing from both other values by 2 or more. Note: abs(num) computes the absolute value of a number.

close_far(1, 2, 10) → True
close_far(1, 2, 3) → False
close_far(4, 1, 3) → True
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def close_far(a, b, c):

See also Python Example Code. Python help docs: Python Strings | Python Lists | Python If Boolean

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Forget It! -- delete my code for this problem 215.0

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