Python > Logic-1 > in1to10
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Given a number n, return True if n is in the range 1..10, inclusive. Unless "outsideMode" is True, in which case return True if the number is less or equal to 1, or greater or equal to 10. in1to10(5, False) → True in1to10(11, False) → False in1to10(11, True) → True ...Save, Compile, Run def in1to10(n, outside_mode): See also Python Example Code. Python help docs: Python Strings | Python Lists | Python If Boolean prev  |  next  |  chance   |  CodingBat  >  Logic-1

Forget It! -- delete my code for this problem 121.0

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