Java > Demo > arrayLike
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We'll say that an array "likes" a particular value if at least half of the elements in the array differ from the value by 2 or less. (This is an example problem where the solution code is provided. Click the Go button to run the problem. JavaBat has many practice coding problems like this with immediate feedback.) arrayLike({1, 6, 8, 7, 0, 0}, 8) → true arrayLike({1, 6, 8, 7, 0, 0}, 4) → false arrayLike({1, 6, 8, 7, 0, 0}, 2) → true ...Save, Compile, Run public boolean arrayLike(int[] nums, int value) { int inRange = 0; for (int i=0; i<nums.length; i++) { if ((nums[i] >= value-2) && (nums[i] <= value+2)) { inRange++; } } return (inRange >= (nums.length + 1)/2); } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  Demo

Forget It! -- delete my code for this problem 903.0

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