Java > String-2 > xyzThere
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Return true if the given string contains an appearance of "xyz" where the xyz is not directly preceeded by a period (.). So "xxyz" counts but "x.xyz" does not. xyzThere("abcxyz") → true xyzThere("abc.xyz") → false xyzThere("xyz.abc") → true ...Save, Compile, Run public boolean xyzThere(String str) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  String-2

Forget It! -- delete my code for this problem 218.0

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