Java > AP-1 > wordsWithout
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Given an array of strings, return a new array without the strings that are equal to the target string. One approach is to count the occurrences of the target string, make a new array of the correct length, and then copy over the correct strings. wordsWithout({"a", "b", "c", "a"}, "a") → {"b", "c"} wordsWithout({"a", "b", "c", "a"}, "b") → {"a", "c", "a"} wordsWithout({"a", "b", "c", "a"}, "c") → {"a", "b", "a"} ...Save, Compile, Run public String[] wordsWithout(String[] words, String target) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  AP-1

Forget It! -- delete my code for this problem 242.0

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