Java > Array-3 > seriesUp
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Given n>=0, create an array with the pattern {1,    1, 2,    1, 2, 3,   ... 1, 2, 3 .. n} (spaces added to show the grouping). Note that the length of the array will be 1 + 2 + 3 ... + n, which is known to sum to exactly n*(n + 1)/2. seriesUp(3) → {1, 1, 2, 1, 2, 3} seriesUp(4) → {1, 1, 2, 1, 2, 3, 1, 2, 3, 4} seriesUp(2) → {1, 1, 2} ...Save, Compile, Run public int[] seriesUp(int n) { } See also Java Example Code. Java help docs: If Boolean Logic | Strings | While and For Loops | Arrays and Loops prev  |  next  |  chance   |  CodingBat  >  Array-3

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