If Boolean

Python boolean operators are spelled out as the words "and" "or" "not", instead of the && syntax in other languages. The following a_bigger() function should return True if the int parameter a is larger than b by 2 or more.

def a_bigger(a, b):
  if a > b and (a - b) >= 2:
    return True
  else:
    return False
  ## Can all be written as just
  ## return (a > b and (a - b) >= 2)

Another technique is to build up the answer in a local "result" variable which is set in various if-statements and returned on the last line:

def a_bigger(a, b):
  result = False
  if a > b and a-b >= 2:
    result = True

  ## Could have more if-logic to set result

  return result

Make a string out of text by enclosing it in single or double quotes "like this", and use + to combine strings to make bigger strings. The with_no() example function takes in a string and returns a new string with "No:" added at the front.

def with_no(str):
  return "No:" + str;

The function len(str) returns the length of a string, and str[i] returns the char at index i.

This two_e() example method returns True if the string contains exactly two 'e' chars. The loop for ch in str: is a standard loop which iterates over the chars in a string:

def two_e(str):
  count = 0
  for ch in str:  ## this loops over each char in the string
    if ch == 'e':
      count = count + 1

  if count == 2:
    return True
  else:
    return False
  ## this last if/else can be written simply as "return (count == 2)"

The same as with strings, the len() function returns the length of a list, and [i] accesses the ith element. The same loop as above, for num in nums:, will loop over all the values in a list. However, here is another way to do it: The function range(n) returns 0, 1, 2, ... n-1. This can be used to write a loop for i in range(len(list)): over the index numbers of a list (or string). This makes it easier to refer to relative (i-1) or (i+1) elements inside the loop. This pair_13() example function returns True if the list contains a pair of 13's next to each other.

def pair_13(nums) {
  for i in range(len(nums) - 1):
    if nums[i]==13 and nums[i+1]==13:
      return True

  return False ## if we get here, there was not a pair of 13's

  ## Note: the -1 inside the range() stops the loop one short of the full length,
  ## so the code in the loop can refer to nums[i+1]

None Result

If a function does not include a "return", then by default it returns the special value None. So if all of your results are None, you probably just forgot to put in the return. Or perhaps the if/else structure doesn't call return in some cases, so in those cases None is the result.